In Perl, why do I need to @b = @{dclone(\@a)}? Why can't I just @b = dclone(\@a)?
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by synapz
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Published on 2010-01-06T16:04:25Z
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2010/05/31
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I have an array of various things including scalars and arrays. I want to make a copy of it, and tried the following:
@b = dclone(\@a)
but then when I try to read one of the scalar values from b, I get nothing back.
Everything appears to work when I copy it this way, though:
@b = @{dclone(\@a)}
What is the reason?
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